• # question_answer A particle is moving eastward with a velocity 10 m/s. In 10 s the velocity changes to 10 m/s northwards. The average acceleration during this time is: A) $\sqrt{2}\,m/{{s}^{2}}N-W$         B) $\frac{1}{2}\,m/{{s}^{2}}\,N-W$C) $\sqrt{2}\,m/{{s}^{2}}\,N-E$        D)  0

Average accelerations$=\frac{\Delta \vec{v}}{\Delta t}=\frac{|{{{\vec{v}}}_{2}}-{{{\vec{v}}}_{1}}|}{\Delta t}$ $\therefore$Magnitude of average acceleration $=\frac{10\sqrt{2}}{10}=\sqrt{2}\frac{m}{{{s}^{2}}}NW.$ Hence, the correction option is [c].