A) \[{{H}_{2}}S{{O}_{4}}>S{{O}_{2}}>{{H}_{2}}S>{{H}_{2}}{{S}_{2}}{{O}_{8}}\]
B) \[N{{a}_{2}}{{S}_{4}}{{O}_{6}}>{{H}_{2}}{{S}_{2}}{{O}_{7}}>N{{a}_{2}}{{S}_{2}}{{O}_{3}}>{{S}_{8}}\]
C) \[{{H}_{2}}S{{O}_{5}}>{{H}_{2}}S{{O}_{3}}>SC{{l}_{2}}>{{H}_{2}}S\]
D) \[S{{O}_{2}}^{2+}>S{{O}_{4}}^{2-}>S{{O}_{3}}^{2-}>HS{{O}_{4}}^{-}\]
Correct Answer: C
Solution :
Compound Oxidation state \[{{H}_{2}}S{{O}_{5}}\] +8 \[{{H}_{2}}S{{O}_{3}}\] +4 \[SC{{l}_{2}}\] +2 \[{{H}_{2}}S\] -2 Hence, the correct option is [c].
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