A) \[n+\frac{x-m}{2}+y\]
B) \[\frac{x-m}{4}\]
C) \[2y-n+x-m\]
D) \[n+\frac{x-m}{4}-y\]
Correct Answer: D
Solution :
\[_{y}^{x}A\to _{n}^{m}B+{{a}_{2}}{{\alpha }^{4}}+{{b}_{-1}}{{\beta }^{0}}\] \[x=m+4a\frac{x-m}{4}=a\] \[y=n+2\times a-b\] \[b=(n-y)+2a\] \[b=(n-y)+\frac{2}{4}(x-m)\] \[=n+\frac{x-m}{4}-y\] Hence, the correct option is [d].
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