NEET Sample Paper NEET Sample Test Paper-17

  • question_answer
    lionization potential of hydrogen atom is 13.6 Hydrogen atom in the ground state is excited by monochromatic radiation of photons of energy 12.1 eV. The number of spectral lines emitted by the hydrogen atom, according to Bohr's theory, will be

    A)  one               

    B)  two                            

    C)  three              

    D)  four

    Correct Answer: C

    Solution :

    Energy gained by electron \[=13.6-12.1=1.5\text{ }eV.\]The electron will jump to an orbit of principal Quantum number n given by \[13.6/{{n}^{2}}=1.5\] Or\[{{n}^{2}}=13.6/1.5=9\]or \[n=3.\] Hence, the possible transitions are \[n=3\]to \[n=2,\,n=3\]to n = 1 and n = 2 to n = 1. Thus three spectral Lines will be emitted. Hence, the correction option is [c].


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