NEET Sample Paper NEET Sample Test Paper-16

  • question_answer 58) In a chemical equilibrium, the rate constant of forward reaction is \[75\times {{10}^{-4}}\]and the equilibrium constant is 1.5. The rate constant backward reaction is

    A) \[4.5\times {{10}^{4}}\]                  

    B) \[5\times {{10}^{-4}}\]       

    C)      \[2.5\times {{10}^{-4}}\]    

    D)      \[6\times {{10}^{4}}\]                     

    Correct Answer: A

    Solution :

    As \[K=\frac{\text{Rate of forward reaction}}{\text{Rate of backward reaction}}=\frac{{{K}_{t}}}{{{K}_{b}}}\] \[=\frac{7.5\times {{10}^{-4}}}{{{K}_{b}}}\] or         \[{{K}_{b}}=\frac{7.5\times {{10}^{-4}}}{1.5}\] \[=5\times {{10}^{-4}}\] Hence, the correct option is (a).

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