A) \[A{{g}_{2}}O+{{H}_{2}}{{O}_{2}}\to 2Ag+{{H}_{2}}O+{{O}_{2}}\]
B) \[{{H}_{2}}{{O}_{2}}+S{{O}_{2}}\to {{H}_{2}}S{{O}_{4}}\]
C) \[2KI+{{H}_{2}}{{O}_{2}}\to 2KOH+{{I}_{2}}\]
D) \[PbS+4{{H}_{2}}{{O}_{2}}\to PbS{{O}_{4}}+4{{H}_{2}}O\]
Correct Answer: A
Solution :
Here, \[{{H}_{2}}{{O}_{2}}\]acts as a reducing agent. \[Ag{{O}_{2}}+{{H}_{2}}{{O}_{2}}\to 2Ag+{{H}_{2}}O+{{O}_{2}}\] Hence, the correct option is (a).
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