• # question_answer 51) ${{H}_{2}}{{O}_{2}}$is a reducing agent in the reaction A) $A{{g}_{2}}O+{{H}_{2}}{{O}_{2}}\to 2Ag+{{H}_{2}}O+{{O}_{2}}$B) ${{H}_{2}}{{O}_{2}}+S{{O}_{2}}\to {{H}_{2}}S{{O}_{4}}$C) $2KI+{{H}_{2}}{{O}_{2}}\to 2KOH+{{I}_{2}}$D) $PbS+4{{H}_{2}}{{O}_{2}}\to PbS{{O}_{4}}+4{{H}_{2}}O$

Here, ${{H}_{2}}{{O}_{2}}$acts as a reducing agent. $Ag{{O}_{2}}+{{H}_{2}}{{O}_{2}}\to 2Ag+{{H}_{2}}O+{{O}_{2}}$ Hence, the correct option is (a).