• # question_answer Which energy state of the triply ionized beryllium$(B{{e}^{+++}})$has the same electron orbital radius as that of the ground state of hydrogen? Given Z for beryllium = 4. A) n = 1                          B) n = 2  C)      n = 3              D)      n = 4

We know that Z = 4 and it is given that $r={{a}_{0}}$ $\therefore$    ${{a}_{0}}={{a}_{0}}\frac{{{n}^{2}}}{4}\Rightarrow {{n}^{2}}=4\Rightarrow n=2$ Hence, the correction option is (b).