• # question_answer On $\alpha -$decay ${{\,}_{92}}{{U}^{238}}$ produces A) $_{92}N{{p}^{238}}$                  B) $_{90}T{{h}^{234}}$C) $_{91}p{{a}^{234}}$                   D) ${{\,}_{92}}{{U}^{234}}$

$_{92}^{238}U\overset{\alpha -decay}{\mathop{\to }}\,{}_{90}^{234}Th+_{2}^{4}He$ Hence, the correct option is [b].