NEET Sample Paper NEET Sample Test Paper-14

  • question_answer The block of mass (M) moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is

    A)  0                                

    B)  \[\frac{M{{L}^{2}}}{K}\]

    C) \[\sqrt{(MK)}L\]                      

    D)  \[\frac{K{{L}^{2}}}{2M}\]

    Correct Answer: C

    Solution :

    When block of mass M collides with the spring its kinetic energy gets converted into elastic potential energy of the spring. From the law of conservation of energy \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}K{{L}^{2}},\]\[\therefore \,v=\sqrt{\frac{K}{M}}L.\]so, Its maximum momentum, \[P=Mv=M\sqrt{\frac{K}{M}}L=\sqrt{MK}.L.\] Hence, the correction option is [c].


You need to login to perform this action.
You will be redirected in 3 sec spinner