• # question_answer At a particular locus, frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium? A)  0.36                           B)  0.16C)  0.24                           D)  0.48

The mathematical expression to calculate allele frequency can be given as p + q = 1. Where p represents the frequency of dominant allele and q represents the frequency of recessive allele. The binomial expression of Hardy-Weinberg's law to calculate genotype frequency is ${{p}^{2}}+2pq+{{q}^{2}}=1.$ Where${{p}^{2}}=$homozygous dominant 2pq = heterozygous dominant ${{q}^{2}}=$homozygous recessive Frequency of heterozygous individuals $=2\times 0.6\times 0.4=0.48$