A) 2
B) \[\frac{1}{2}\]
C) \[\frac{1}{\sqrt{2}}\]
D) \[\sqrt{2}\]
Correct Answer: B
Solution :
Potential energy, \[U=-\frac{G{{M}_{e}}m}{{{R}_{e}}}or\left| U \right|=\frac{G{{M}_{e}}m}{{{R}_{e}}}\] Kinetic energy, \[K=\frac{1}{2}\frac{G{{M}_{e}}m}{{{R}_{e}}}\] Thud, \[\frac{K}{\left| U \right|}=\frac{1}{2}\frac{G{{M}_{e}}m}{{{R}_{e}}}\times \frac{{{R}_{e}}}{G{{M}_{e}}m}=\frac{1}{2}\] Aliter: For a moving satellite kinetic energy \[=\frac{GMm}{2r}\] Potential energy \[=\frac{-G\,Mm}{r}\] \[\therefore \] \[\frac{\text{Kinetic}\,\text{energy}}{\text{Potential}\,\text{energy}}\text{=}\frac{\text{1}}{\text{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
