A) 1.4
B) 2.0
C) 2.8
D) 4.0
Correct Answer: A
Solution :
Average velocity \[=\sqrt{\frac{8\,RT}{\pi \,m}}\] \[\therefore \] \[{{V}_{av}}\propto \sqrt{T}\] \[\therefore \] \[\frac{{{\left( {{V}_{av}} \right)}_{2}}}{{{\left( {{V}_{av}} \right)}_{1}}}=\sqrt{\frac{2T}{T}}=1.4\]
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