| \[{{N}_{2}}+3{{H}_{2}}\rightleftharpoons 2N{{H}_{3}};{{K}_{1}}\] |
| \[{{N}_{2}}+{{O}_{2}}\rightleftharpoons 2NO;{{K}_{2}}\] |
| \[{{H}_{2}}\frac{1}{2}{{O}_{2}}\rightleftharpoons {{H}_{2}}O;{{K}_{3}}\] |
| The equilibrium constant of the reaction\[2N{{H}_{3}}+\frac{5}{2}{{O}_{2}}\rightleftharpoons 2NO+3{{H}_{2}}O\]in terms of \[{{K}_{1}},{{K}_{2}}\]and \[{{K}_{3}}\] |
A) \[K=\frac{{{K}_{2}}\times K_{3}^{2}}{{{K}_{1}}}\]
B) \[K=\frac{K_{2}^{2}\times {{K}_{3}}}{{{K}_{1}}}\]
C) \[K=\frac{{{K}_{1}}\times {{K}_{2}}}{{{K}_{3}}}\]
D) \[K=\frac{{{K}_{2}}\times K_{3}^{3}}{{{K}_{1}}}\]
Correct Answer: D
Solution :
For equilibrium, [a]\[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)\] \[{{K}_{1}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\] ?(i) [b]\[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2NO(g)\] \[{{K}_{2}}=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]}\] ?(ii) [c] \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\rightleftharpoons {{H}_{2}}O(g)\] \[{{K}_{3}}=\frac{[{{H}_{2}}O]}{[{{H}_{2}}]{{[{{O}_{2}}]}^{1/2}}}\] ?(iii) For reaction, \[2N{{H}_{3}}(g)+\frac{5}{2}{{O}_{2}}(g)\rightleftharpoons 2NO(g)+3{{H}_{2}}O(g)\] \[K=\frac{{{[NO]}^{2}}{{[{{H}_{2}}O]}^{3}}}{{{[N{{H}_{3}}]}^{2}}{{[{{O}_{2}}]}^{5/2}}}\] (iv) For getting K, we must do \[K_{3}^{3}=\frac{{{[{{H}_{2}}O]}^{3}}}{{{[{{H}_{2}}]}^{3}}{{[{{O}_{2}}]}^{3/2}}}\] (v) From eqs. (i) (ii) and (v) \[K=\frac{{{K}_{2}}\times K_{3}^{3}}{{{K}_{1}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
