A) \[\gamma -\]rays
B) X-rays
C) Infrared rays
D) Ultraviolet rays
Correct Answer: B
Solution :
E = 15 Kev \[\lambda =\frac{hc}{E}=\frac{6.6\times {{10}^{-19}}\times 3\times {{10}^{8}}}{15\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}\] \[\lambda =0.8\overset{\text{o}}{\mathop{\text{A}}}\,=1\overset{\text{o}}{\mathop{\text{A}}}\,\]
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