A) 882
B) 1323
C) 1764
D) 3528
Correct Answer: D
Solution :
\[{{1}^{3}}+{{2}^{3}}+{{3}^{3}}+{{4}^{3}}+{{5}^{3}}+{{6}^{\mathsf{3}}}=441\] (Given) \[{{2}^{3}}+{{4}^{3}}+{{6}^{3}}+{{8}^{3}}+{{10}^{3}}+{{12}^{3}}\] \[=8\,\,({{1}^{3}}+{{2}^{3}}+{{3}^{3}}+{{4}^{3}}+{{5}^{3}}+{{6}^{3}})\] \[=8\times 441=3528\]You need to login to perform this action.
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