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SSC Sample Paper Mock Test-7 SSC CGL Tear-II Paper-1

  • question_answer
    The be smallest number added to 680621 to make the sum a perfect square is

    A)  4

    B)  5

    C)  6

    D)  8

    Correct Answer: A

    Solution :

    \[\therefore \]      \[{{(824)}^{2}}<680621<{{(825)}^{2}}\] \[\therefore \] Required number \[=[{{(825)}^{2}}-680621]=4\]


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