A) \[144\,\,c{{m}^{2}}\]
B) \[180\,\,c{{m}^{2}}\]
C) \[154\,\,c{{m}^{2}}\]
D) \[176\,\,c{{m}^{2}}\]
Correct Answer: C
Solution :
| B. Side of the square\[=\sqrt{121}=11\,\,\text{cm}\] |
| \[\therefore \]Length of the wire\[=4\times \text{side}\,\text{=}\,\text{4}\times \text{11=}\,\text{44}\,\,\text{cm}\] |
| Now, the wire is bent into the form of a circle |
| If the radius of the circle be r cm, then |
| \[\therefore \] \[2\pi r=44\] |
| \[\Rightarrow \] \[=\frac{\sqrt{9}}{\sqrt{4}}=\frac{3}{2}\] |
| \[\therefore \]Area of the circle \[=\pi {{r}^{2}}=\frac{22}{7}\times 7\times 7=154\,\,\text{c}{{\text{m}}^{2}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
