A) \[1\frac{1}{2}\,\,yr\]
B) \[2\,\,yr\]
C) \[2\frac{1}{2}\,\,yr\]
D) \[3\,\,yr\]
Correct Answer: A
Solution :
| The rate of interest is compounded half yearly, |
| \[\therefore \] r = 10% per half year |
| Let time \[=\frac{T}{2}\]year = half year |
| According to the question, |
| Amount = Principal \[{{\left( 1+\frac{\text{Rate}}{100} \right)}^{\text{Time}}}\] |
| \[13310=10000{{\left( 1+\frac{10}{100} \right)}^{T}}\Rightarrow \frac{13310}{10000}={{\left( \frac{11}{10} \right)}^{T}}\] |
| \[\Rightarrow \] \[{{\left( \frac{11}{10} \right)}^{T}}=\frac{1331}{1000}\Rightarrow {{\left( \frac{11}{10} \right)}^{T}}={{\left( \frac{11}{10} \right)}^{3}}\] |
| \[\therefore \] T = 3 half yr\[=1\frac{1}{2}\]yr |
You need to login to perform this action.
You will be redirected in
3 sec
