2. Sample Papers
  3. SSC

SSC Sample Paper Mock Test-6 SSC CGL Tear-II Paper-1

  • question_answer
    A train covers a distance of 3584 km in 2 days 8 h. If it covers 1440 km on the first day and 1608 km on the second day, by how much does the average speed of the train for the remaining part journey differ from that for the entire journey?

    A)  3 km/h more

    B)  3 km/h less   

    C)  4 km/h more    

    D)  5 km/h less   

    Correct Answer: A

    Solution :

    Remaining distance \[=(3584-1440-1608)\,\,km\] \[=5316\,\,km\] This distance is covered at the rate of \[\frac{536}{8}=67\,\,km/h\] Average speed of whole journey \[=\frac{3584}{56}=64\,\,km/h\] \[\therefore \] Required difference \[=(67-64)\,\,km/h\] \[=3km/h\,\,\text{more}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner