SSC Sample Paper Mock Test-5 SSC CGL Tear-II Paper-1

  • question_answer
    Factorize value of \[{{a}^{3}}-\frac{1}{{{a}^{3}}}-2a+\frac{2}{a}\]is

    A)  \[\left( a+\frac{1}{a} \right)\left( {{a}^{2}}+\frac{1}{{{a}^{2}}} \right)-2\left( a-\frac{1}{a} \right)\]

    B)  \[\left( a-\frac{1}{a} \right)\left( {{a}^{2}}+\frac{1}{{{a}^{2}}}+1 \right)+2\left( a-\frac{1}{a} \right)\]

    C)  \[\left( a+\frac{1}{a} \right)\left( a-\frac{1}{a} \right)\]

    D)  \[\left( a-\frac{1}{a} \right)\left( {{a}^{2}}+\frac{1}{{{a}^{2}}}-1 \right)\]

    Correct Answer: D

    Solution :

    \[{{a}^{3}}-\frac{1}{{{a}^{3}}}-2a+\frac{2}{a}={{a}^{3}}-{{\left( \frac{1}{a} \right)}^{3}}-2\left( a-\frac{1}{a} \right)\]
    \[=\left( a-\frac{1}{a} \right)\left( {{a}^{2}}+\frac{1}{{{a}^{2}}}+1 \right)-2\left( a-\frac{1}{a} \right)\]
    \[=\left( a-\frac{1}{a} \right)\left[ {{a}^{2}}+\frac{1}{{{a}^{2}}}+1-2 \right]\]
    \[=\left( a-\frac{1}{a} \right)\left( {{a}^{2}}+\frac{1}{{{a}^{2}}}-1 \right)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner