A) \[(x-2y-4)\]and \[(x-2y+2)\]
B) \[(x-y+2)\]and \[(x-4y+4)\]
C) \[(x-2+2)\]and \[(x-4y-4)\]
D) \[(x+2y-4)\]and\[(x+2y+2)\]
Correct Answer: A
Solution :
\[{{x}^{2}}+4{{y}^{2}}+4y-4xy-2x-8\] \[={{(x-2y)}^{2}}-2(x-2y)-8\] \[={{(x-2y)}^{2}}-4\,\,(x-2y)+2\,\,(x-2y)-8\] \[=(x-2y-4)(x-2y+2)\]
You need to login to perform this action.
You will be redirected in
3 sec
