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SSC Sample Paper Mock Test-3 SSC CGL Tear-II Paper-1

  • question_answer
    \[\frac{{{(0.87)}^{3}}+{{(0.13)}^{3}}}{{{(0.87)}^{2}}+{{(0.13)}^{2}}-0.87\times 0.13}\]is equal to

    A)  0.13                            

    B)  0.87

    C)  1        

    D)  0.74

    Correct Answer: C

    Solution :

    \[\frac{{{a}^{3}}+{{b}^{3}}}{{{a}^{2}}+{{b}^{2}}-ab}=\frac{(a+b)({{a}^{2}}+{{b}^{2}}-ab)}{({{a}^{2}}+{{b}^{2}}-ab)}=(a+b)\] \[=0.87+0.13=1\](If a = 0. 87 and b = 0. 13)                        


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