A) \[p=c\sqrt{1+{{m}^{2}}}\]
B) \[c=p\sqrt{1+{{m}^{2}}}\]
C) \[cp=\sqrt{1+{{m}^{2}}}\]
D) \[{{p}^{2}}+{{c}^{2}}+{{m}^{2}}=1\]
Correct Answer: B
Solution :
If the given lines represent the same line, then the lengths of the perpendiculars from the origin to the lines are equal, So that \[\frac{c}{\sqrt{1+{{m}^{2}}}}=\frac{p}{\sqrt{{{\cos }^{2}}\alpha +{{\sin }^{2}}\alpha }}\Rightarrow c=p\sqrt{1+{{m}^{2}}}\]
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