A) 1: 4
B) 2 : 1
C) 1: 2
D) 4 : 1
Correct Answer: D
Solution :
Volume of original cone\[{{V}_{1}}=\frac{1}{3}\pi {{r}^{2}}h\] Now, radius of new cone \[{{r}_{1}}=2r\] Height \[{{h}_{1}}=h\] \[\therefore \] Volume \[{{V}_{2}}=\frac{1}{3}\pi r_{1}^{2}{{h}_{1}}=\frac{1}{3}\pi {{(2r)}^{2}}\times h=\frac{4}{3}\pi {{r}^{2}}h\] \[\therefore \] \[\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{\frac{4}{3}\pi {{r}^{2}}h}{\frac{1}{3}\pi {{r}^{2}}h}=4:1\]
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