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SSC Sample Paper Mock Test-2 SSC CGL Tear-II Paper-1

  • question_answer
    If \[\frac{\frac{1}{4}-\frac{1}{6}-\frac{1}{48}}{\frac{1}{4}-\left( \frac{1}{6}-\frac{1}{48} \right)}\div \frac{\frac{1}{4}\times \frac{1}{6}-\frac{1}{48}}{\frac{1}{4}\times \left( \frac{1}{6}-\frac{1}{48} \right)}=x,\] the value of x is

    A)  \[\frac{20}{21}\]                                  

    B)  \[-\frac{21}{20}\]

    C)  \[\frac{21}{20}\]          

    D)  \[-\frac{20}{21}\]

    Correct Answer: C

    Solution :

    Here,
    \[\frac{\frac{1}{4}-\frac{1}{6}-\frac{1}{48}}{\frac{1}{4}-\left( \frac{1}{6}-\frac{1}{48} \right)}\div \frac{\frac{1}{4}\times \frac{1}{6}-\frac{1}{48}}{\frac{1}{4}\times \left( \frac{1}{6}-\frac{1}{48} \right)}=x\]
    \[\Rightarrow \]\[x=\frac{\frac{12-8-1}{48}}{\frac{12-(8-1)}{48}}\div \frac{\frac{1}{24}-\frac{1}{48}}{\frac{1}{4}\times \left( \frac{8-1}{48} \right)}\]
    \[\therefore \]\[x=\frac{\frac{3}{48}}{\frac{5}{48}}\div \frac{\frac{2-1}{48}}{\frac{7}{4\times 48}}\]
    \[=\frac{3}{5}\div \frac{4}{7}=\frac{21}{20}\]
                           


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