A) 24 km/h
B) 25 km/h
C) 27 km/h
D) 28 km/h
Correct Answer: B
Solution :
Let the length of the train be \[x\,\,\text{km}\]and its speed be\[y\,\,\text{km/h}\text{.}\]Speed of the train relative to first man\[=(y-3)\,\,\text{km/h}\]Speed of the train relative to second man \[=(y-5)\,\,\text{km/h}\] \[\frac{x}{(y-3)}=\frac{10}{(60\times 60)}\]and \[\frac{x}{(y-5)}=\frac{11}{60\times 60}\] \[\Rightarrow \] \[y-3=360x\]and \[11y-55=3600x\] \[\Rightarrow \] \[10y-30=3600x\]and \[11y-55=3600x\] \[\Rightarrow \] \[10y-30=11y-55\]\[\Rightarrow \]\[y=25\] \[\therefore \] Speed of the train = 25 km/h
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