A) \[x=3.2\]and \[y=2.3\]
B) \[x=1\]and \[y=0.1\]
C) \[x=2\]and \[y=1.1\]
D) \[x=1.2\]and \[y=0.3\]
Correct Answer: A
Solution :
Given, \[x-y=0.9\] ...(i) and \[11\,\,{{(x+y)}^{-1}}=2\] \[\Rightarrow \] \[2x+2y=11\] ...(ii) On multiplying Eq. (i) by 2 and adding Eqs. (i) and (ii), we get \[4x=12.8\]\[\Rightarrow \]\[x=3.2\] From Eq. (i), \[y=3.2-0.9=2.3\] \[x-2.3=9\] \[\therefore \] \[x=3.2\]
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