SSC Sample Paper Mock Test-19 SSC CGL Tear-II Paper-1

  • question_answer
    A soldier goes to a warfield and runs in the following manner. From the starting point, he goes West 25 m, then due North 60 m, then due East 80 m and finally due South 12 cm. The distance between the starting point and the finishing point is   

    A)         177 m

    B)  103 m        

    C)  83 m   

    D)  73 m   

    Correct Answer: D

    Solution :

     
    Let P be the starting point of his run, then PT is the distance between the starting and the finishing point.
    \[\therefore \]      \[PU=RQ-ST=60-12=48\,\,\text{m}\]
    \[TU=RS-QP=80-25=55\,\,\text{m}\]
    \[\therefore \]In \[\Delta PUT,\]\[P{{T}^{2}}={{(PU)}^{2}}+{{(TU)}^{2}}\]
    \[\therefore \]      \[PT=\sqrt{{{(48)}^{2}}+{{(55)}^{2}}}=\sqrt{5329}=73\,\,\text{m}\]


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