A) 1 : 1
B) 2 : 1
C) 1 : 2
D) 3 : 1
Correct Answer: C
Solution :
Let side \[AB=BC=CD=AD=x\] Diagonal \[=\sqrt{2}x\] \[\therefore \] Radius of incircle \[=\frac{x}{2}\] Radius of circumcircle \[=\frac{\sqrt{2}x}{2}=\frac{x}{\sqrt{2}}\] \[\therefore \] Required ratio\[=\left( \frac{\pi {{x}^{2}}}{4}:\frac{\pi {{x}^{2}}}{2} \right)=2:4=1:2\]You need to login to perform this action.
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