A) Rs. 1200
B) Rs. 1225
C) Rs. 1250
D) Rs. 1300
Correct Answer: C
Solution :
Let the sum be Rs. x. \[\therefore \] \[1352=x{{\left( 1+\frac{4}{100} \right)}^{2}}\]\[\Rightarrow \]\[1352=x{{\left( \frac{26}{25} \right)}^{2}}\] \[\therefore \] \[x=\frac{1352\times 25\times 25}{26\times 26}\]= Rs. 1250You need to login to perform this action.
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