A) \[1\]
B) \[0\]
C) \[-\frac{15}{2}\]
D) \[-\frac{1}{2}\]
Correct Answer: B
Solution :
\[1+\frac{4}{2+\frac{3}{\frac{10-1}{2}}}-\frac{1}{2}\times 5=1+\frac{4}{2+\frac{6}{9}}-\frac{5}{2}\] \[=1+\frac{4}{2+\frac{2}{3}}-\frac{5}{2}=1+\frac{4}{\frac{8}{3}}-\frac{5}{2}\] \[=1+\frac{4\times 3}{8}-\frac{5}{2}\] \[=1+\frac{3}{22}-5\] \[=\frac{2+3-5}{2}=0\]
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