A) 4 h
B) 4 h 15 min
C) 3 h 15 min
D) 3 h 45 mm
Correct Answer: D
Solution :
A tap can fill the tank in 6 h. In filling the tank to its half, Time required = 3 h Remaining pan \[=\frac{1}{2}\] \[\because \]1 tap takes 6 h to fill the tank \[\therefore \]4 taps take to fill \[\frac{1}{2}\]of the tank \[=\frac{6}{4}\times \frac{1}{2}=\frac{3}{4}\text{h}\] \[\therefore \]Total time \[=3+\frac{3}{4}=3\frac{3}{4}\text{h}\] = 3 h 45 min
You need to login to perform this action.
You will be redirected in
3 sec
