SSC Sample Paper Mock Test-19 SSC CGL Tear-II Paper-1

  • question_answer
    A hemisphere and a cone have equal bases. If their heights are also equal, the ratio of their curved surfaces will be

    A)  \[1:\sqrt{2}\]

    B)  \[\sqrt{2}:1\]

    C)  \[1:2\]  

    D)  \[2:1\]

    Correct Answer: B

    Solution :

    According to the question, Base of hemisphere = Base of cone (i.e.. radius of hemisphere) = Base of cone                 ...(i) i.e., radius of hemisphere = radius of come    ...(ii) and height of cone We know that, Height of hemisphere = radius of hemisphere or height of cone = radius of hemisphere    [From Eq. (i)] or height of cone = radius of cone         [From Eq. (ii)] Now, curved surface area of hemisphere \[=\pi \sqrt{{{r}^{2}}+{{h}^{2}}}\] \[=\pi r\sqrt{{{r}^{2}}+{{h}^{2}}}\]              \[(\because r=h)\] \[=\pi r\sqrt{2{{r}^{2}}}\] \[=\pi r\times \sqrt{2r}\] \[=\sqrt{2}\pi {{r}^{2}}\] \[\therefore \] Ratio of curved surface areas of hemisphere and cone \[=2\pi {{r}^{2}}:\sqrt{2}\pi {{r}^{2}}\] \[=2:\sqrt{2}\] \[=\sqrt{2}:1\]


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