A) 70000
B) 69200
C) 68921
D) 68911
Correct Answer: C
Solution :
\[P={{P}_{0}}{{\left( 1+\frac{R}{100} \right)}^{T}}=64000{{\left( 1+\frac{5}{200} \right)}^{3}}\] \[=64000{{\left( \frac{41}{40} \right)}^{3}}\] \[=\frac{64000\times 41\times 41\times 41}{40\times 40\times 40}\] \[=68921\]You need to login to perform this action.
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