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SSC Sample Paper Mock Test-19 SSC CGL Tear-II Paper-1

  • question_answer
    If p = 999, then the value of\[\sqrt[3]{p\,\,({{p}^{2}}+3p+3)+1}\]

    A) 1000

    B)  999            

    C)  998

    D)  1002   

    Correct Answer: A

    Solution :

    \[P=999\]                      (Given) Now,     \[\sqrt[3]{P({{P}^{2}}3P+3)+1}\] \[=\sqrt[3]{{{P}^{3}}+3{{P}^{2}}+3P+1}\] \[=\sqrt[3]{{{(P+1)}^{3}}}=P+1\] \[=999+1=1000\]


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