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SSC Sample Paper Mock Test-19 SSC CGL Tear-II Paper-1

  • question_answer
    The value of\[\left( 1+\frac{1}{2} \right)\left( 1+\frac{1}{3} \right)\left( 1+\frac{1}{4} \right)...\left( 1+\frac{1}{120} \right)\]is

    A) 30

    B)  40.5

    C)  60.5    

    D)  121

    Correct Answer: C

    Solution :

    \[\left( \frac{2+1}{2} \right)\left( \frac{3+1}{3} \right)\left( \frac{4+1}{4} \right)...\left( \frac{120+1}{120} \right)\] \[=\frac{3}{2}\times \frac{4}{3}\times \frac{5}{4}\times ...\times \frac{121}{120}=\frac{121}{2}=60.5\]


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