A) \[\frac{1}{15}\]
B) \[\frac{1}{30}\]
C) \[\frac{2}{15}\]
D) \[15\]
Correct Answer: B
Solution :
Let the radius of wire = r cm Volume of copper rod \[=\pi \times {{\left( \frac{1}{2} \right)}^{2}}\times 8=2\pi \,\,\text{c}{{\text{m}}^{\text{3}}}\] Volume of wire \[=\pi {{r}^{2}}\times 1800=1800\pi {{r}^{2}}\,\,\text{c}{{\text{m}}^{\text{3}}}\] Clearly, \[1800\pi {{r}^{2}}=2\pi \] \[\Rightarrow \] \[{{r}^{2}}=\frac{1}{900}\]\[\Rightarrow \]\[r=\frac{1}{30}\]
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