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SSC Sample Paper Mock Test-17 SSC CGL Tear-II Paper-1

  • question_answer
    If a = 4.36, b = 2.39 and c = 1.97, then the value of \[{{a}^{3}}-{{b}^{3}}-{{c}^{3}}-3abc\] is

    A) 3.94     

    B)  2.39

    C)  0

    D)  1

    Correct Answer: C

    Solution :

    Here, \[a-b-c=4.36-2.39-1.97=0\] \[\therefore \]\[{{a}^{3}}-{{b}^{3}}-{{c}^{3}}=3abc\] \[\Rightarrow \]   \[{{a}^{3}}-{{b}^{3}}-{{c}^{3}}-3abc=0\]


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