A) 40
B) 60
C) 65
D) 70
Correct Answer: B
Solution :
Let the number of boys and girls in the class be x and y, respectively. \[\therefore \] \[60x+80y=68\,\,(x+y)\] \[\Rightarrow \] \[60x+80y=68x+68y\] \[\Rightarrow \] \[8x=12y\] \[\Rightarrow \] \[2x=3y\]\[\Rightarrow \]\[y=\frac{2}{3}x\] \[\therefore \]Required percentage \[=\frac{x}{x+y}\times 100\] \[=\frac{x}{x+\frac{2}{3}x}\times 100=\frac{3x}{3x+2x}\times 100\] \[=\frac{3}{5}\times 100=60%\] Short Cut According to the question, Ratio of girls and boys = 8 : 12 = 2 : 3 \[\therefore \] Percentage of boys \[=\frac{3}{5}\times 100=60%\]You need to login to perform this action.
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