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SSC Sample Paper Mock Test-17 SSC CGL Tear-II Paper-1

  • question_answer
    A number is increased by 20% and then again by 20%. By what per cent should the increased number be reduced so as to get back the original number?

    A)  \[30\frac{5}{9}%\]

    B)  \[19\frac{11}{31}%\]

    C)  \[40%\]

    D)  \[44%\]

    Correct Answer: A

    Solution :

    Let the number be 100. After 20%increase, number = 120 After 20% increase of 120, number \[=120\times \frac{120}{100}=144\] \[\therefore \]Per cent decrease \[=\frac{44}{144}\times 100=\frac{275}{9}=30\frac{5}{9}%\]


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