A) \[\frac{38}{109}\]
B) \[\frac{109}{38}\]
C) \[1\]
D) \[\frac{116}{109}\]
Correct Answer: A
Solution :
| \[\frac{2\frac{1}{3}-1\frac{2}{11}}{3+\frac{1}{3+\frac{1}{3+\frac{1}{3}}}}=\frac{\frac{7}{3}-\frac{13}{11}}{3+\frac{1}{3+\frac{1}{10/3}}}=\frac{\frac{77-39}{33}}{3+\frac{1}{3+\frac{3}{10}}}\] |
| \[=\frac{38/33}{3+\frac{1}{33/10}}=\frac{38/33}{3+\frac{10}{33}}=\frac{38/33}{109/33}=\frac{38}{109}\] |
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