SSC Sample Paper Mock Test-16 SSC CGL Tear-II Paper-1

  • question_answer
    If a = 5, b = 3 and c = 2, then the value of\[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}-2ab+2bc-2ac\] is

    A) 0

    B)  100    

    C)  225     

    D)  289

    Correct Answer: A

    Solution :

    As \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}-2ab-2ac+2bc={{(a+b-c)}^{2}}\]\[={{(5-3-2)}^{2}}=0\]


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