SSC Sample Paper Mock Test-16 SSC CGL Tear-II Paper-1

  • question_answer
    The area of an isosceles triangle, each of whose equal sides is 13 cm and whose base is 24 cm is

    A)  \[60\,\,\text{c}{{\text{m}}^{2}}\]

    B)  \[55\,\,\text{c}{{\text{m}}^{2}}\]

    C)  \[50\,\,\text{c}{{\text{m}}^{2}}\]

    D)  \[40\,\,\text{c}{{\text{m}}^{2}}\]

    Correct Answer: A

    Solution :

    Let each equal side = a = 13 cm and base b = 24 cm \[\therefore \] Area of the triangle\[=\frac{1}{2}b\cdot \sqrt{4{{a}^{2}}-{{b}^{2}}}\] \[=\left[ \frac{1}{4}\times 24\times \sqrt{4\times 169-24\times 24} \right]\text{c}{{\text{m}}^{2}}=60\,\,\text{c}{{\text{m}}^{2}}\]


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