A) 25%
B) 20%
C) 15%
D) 30%
Correct Answer: B
Solution :
Let CP of 1 L milk be Rs. 1 |
Then, SP of 1 L mixture = Rs. 1 gain = 25% |
CP of 1 L mixture = Rs. \[\left( \frac{100}{125}\times 1 \right)\]= Rs. \[\frac{4}{5}\] |
CP of 1 L of pure milk CP of 1 L of water |
\[\therefore \] Milk : Water \[=\frac{4}{5}:\frac{1}{5}=4:1\] |
Hence, percentage of water in the mixture |
\[=\left( \frac{1}{5}\times 100 \right)%=20%\] |
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