SSC Sample Paper Mock Test-14 SSC CGL Tear-II Paper-1

  • question_answer
    If \[0.13\div {{P}^{2}}=13,\]then p is equal to

    A) 10

    B)  0.01    

    C)  0.1

    D)  100

    Correct Answer: C

    Solution :

    \[\frac{0.13}{{{p}^{2}}}=13\]\[\Rightarrow \]\[13{{p}^{2}}=0.13\] \[\Rightarrow \]   \[{{p}^{2}}=\frac{0.13}{13}=\frac{13}{100}\times \frac{1}{3}=\frac{1}{100}\] \[\Rightarrow \]   \[p=\frac{1}{10}=0.1\]


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