SSC Sample Paper Mock Test-14 SSC CGL Tear-II Paper-1

The speeds of A and B are in the ratio 3 : 4. A takes 20 min more than B to reach a destination. In what time does A reach the destination?

A) \[1\frac{1}{3}\text{h}\]

B) \[2\,\,\text{h}\]

C) \[1\frac{2}{3}\,\,\text{h}\]

D) \[2\frac{2}{3}\,\,\text{h}\]

Correct Answer: A

Solution :

Let the time taken by A be x hours.

Then, time taken by B =\[\left( x-\frac{20}{60} \right)\text{h}=\left( x-\frac{1}{3} \right)\text{h}\]

Ratio of speeds = Inverse ratio of time taken

\[\therefore \] \[3:4=\left( x-\frac{1}{3} \right):x\]

\[\Rightarrow \] \[\frac{3x-1}{3x}=\frac{3}{4}\]

\[\Rightarrow \] \[12x-4=9x\]

\[\Rightarrow \] \[3x=4\]\[\Rightarrow \]\[x=\frac{4}{3}\text{h}=1\frac{1}{3}\text{h}\]

Required time \[=1\frac{1}{3}\text{h}\]