A) 93.62
B) 103.62
C) 113.62
D) 115.50
Correct Answer: B
Solution :
| For conical part, |
| \[r=\frac{6}{2}=3\,\,\text{cm},\]\[h=4\,\,\text{cm}\,\,l=\sqrt{{{h}^{2}}+{{r}^{2}}}=5\,\,\text{cm}\] |
| Surface area of conical part |
| \[=\pi rl=3.14\times 3\times 5=47.1\,\,\text{c}{{\text{m}}^{2}}\] |
| For hemispherical part, \[r=\frac{6}{2}=3\,\,\text{cm}\] |
| Surface area of hemispherical part \[=2\pi {{r}^{2}}\] |
| \[=2\times 3.14\times 3\times 3=56.52\]sq cm |
| \[\therefore \]Surface area of toy = 47.1+ 56.52 = 103. 62 sq cm |
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