A) \[-3/14\]
B) \[-14/3\]
C) \[1/10\]
D) \[10\]
Correct Answer: D
Solution :
Since, given system of equations, \[x+2y-\,\,3=0\] and \[5x+ky+7=0\] has no solution, \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\] \[\therefore \] \[\frac{1}{5}=\frac{2}{k}\ne \frac{-\,\,3}{7}\] \[\Rightarrow \] \[k-10=0\] \[\therefore \] \[k=10\]
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