SSC Sample Paper Mock Test-14 SSC CGL Tear-II Paper-1

  • question_answer
    What is the value of\[\frac{{{\sin }^{6}}\theta -{{\cos }^{6}}\theta }{{{\sin }^{2}}\theta -{{\cos }^{2}}\theta }?\]

    A)  \[{{\sin }^{4}}\theta -{{\cos }^{4}}\theta \]

    B)  \[1-{{\sin }^{2}}\theta {{\cos }^{2}}\theta \]

    C)  \[1+{{\sin }^{2}}\theta {{\cos }^{2}}\theta \]

    D)  \[1-3{{\sin }^{2}}\theta {{\cos }^{2}}\theta \]

    Correct Answer: B

    Solution :

    \[\frac{{{\sin }^{6}}\theta -{{\cos }^{6}}\theta }{{{\sin }^{2}}\theta -{{\cos }^{2}}\theta }=\frac{{{({{\sin }^{2}}\theta )}^{3}}-{{({{\cos }^{2}}\theta )}^{3}}}{{{\sin }^{2}}\theta -{{\cos }^{2}}\theta }\]
    \[=\frac{({{\sin }^{2}}\theta -{{\cos }^{2}}\theta )({{\sin }^{4}}\theta +{{\cos }^{4}}\theta +{{\sin }^{2}}\theta {{\cos }^{2}}\theta )}{{{\sin }^{2}}\theta -{{\cos }^{2}}\theta }\]
    \[={{\sin }^{4}}\theta +{{\cos }^{4}}\theta +2{{\sin }^{2}}\theta {{\cos }^{2}}\theta -{{\sin }^{2}}\theta {{\cos }^{2}}\theta \]
    \[={{({{\sin }^{2}}\theta +{{\cos }^{2}}\theta )}^{2}}-{{\sin }^{2}}\theta {{\cos }^{2}}\theta =1-{{\sin }^{2}}\theta {{\cos }^{2}}\theta \]


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